\(\int \frac {x^m}{(1+c^2 x^2)^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx\) [460]

Optimal result

Integrand size = 27, antiderivative size = 27 \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\text {Int}\left (\frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2},x\right ) \]

[Out]

Unintegrable(x^m/(c^2*x^2+1)^(5/2)/(a+b*arcsinh(c*x))^2,x)

Rubi [N/A]

Not integrable

Time = 0.09 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx \]

[In]

Int[x^m/((1 + c^2*x^2)^(5/2)*(a + b*ArcSinh[c*x])^2),x]

[Out]

Defer[Int][x^m/((1 + c^2*x^2)^(5/2)*(a + b*ArcSinh[c*x])^2), x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx \\ \end{align*}

Mathematica [N/A]

Not integrable

Time = 1.12 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.07 \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx \]

[In]

Integrate[x^m/((1 + c^2*x^2)^(5/2)*(a + b*ArcSinh[c*x])^2),x]

[Out]

Integrate[x^m/((1 + c^2*x^2)^(5/2)*(a + b*ArcSinh[c*x])^2), x]

Maple [N/A] (verified)

Not integrable

Time = 0.36 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.93

\[\int \frac {x^{m}}{\left (c^{2} x^{2}+1\right )^{\frac {5}{2}} \left (a +b \,\operatorname {arcsinh}\left (c x \right )\right )^{2}}d x\]

[In]

int(x^m/(c^2*x^2+1)^(5/2)/(a+b*arcsinh(c*x))^2,x)

[Out]

int(x^m/(c^2*x^2+1)^(5/2)/(a+b*arcsinh(c*x))^2,x)

Fricas [N/A]

Not integrable

Time = 0.26 (sec) , antiderivative size = 137, normalized size of antiderivative = 5.07 \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\int { \frac {x^{m}}{{\left (c^{2} x^{2} + 1\right )}^{\frac {5}{2}} {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{2}} \,d x } \]

[In]

integrate(x^m/(c^2*x^2+1)^(5/2)/(a+b*arcsinh(c*x))^2,x, algorithm="fricas")

[Out]

integral(sqrt(c^2*x^2 + 1)*x^m/(a^2*c^6*x^6 + 3*a^2*c^4*x^4 + 3*a^2*c^2*x^2 + (b^2*c^6*x^6 + 3*b^2*c^4*x^4 + 3
*b^2*c^2*x^2 + b^2)*arcsinh(c*x)^2 + a^2 + 2*(a*b*c^6*x^6 + 3*a*b*c^4*x^4 + 3*a*b*c^2*x^2 + a*b)*arcsinh(c*x))
, x)

Sympy [N/A]

Not integrable

Time = 82.64 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96 \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\int \frac {x^{m}}{\left (a + b \operatorname {asinh}{\left (c x \right )}\right )^{2} \left (c^{2} x^{2} + 1\right )^{\frac {5}{2}}}\, dx \]

[In]

integrate(x**m/(c**2*x**2+1)**(5/2)/(a+b*asinh(c*x))**2,x)

[Out]

Integral(x**m/((a + b*asinh(c*x))**2*(c**2*x**2 + 1)**(5/2)), x)

Maxima [N/A]

Not integrable

Time = 0.83 (sec) , antiderivative size = 613, normalized size of antiderivative = 22.70 \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\int { \frac {x^{m}}{{\left (c^{2} x^{2} + 1\right )}^{\frac {5}{2}} {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{2}} \,d x } \]

[In]

integrate(x^m/(c^2*x^2+1)^(5/2)/(a+b*arcsinh(c*x))^2,x, algorithm="maxima")

[Out]

-(c*x*x^m + sqrt(c^2*x^2 + 1)*x^m)/((a*b*c^4*x^3 + a*b*c^2*x)*(c^2*x^2 + 1) + ((b^2*c^4*x^3 + b^2*c^2*x)*(c^2*
x^2 + 1) + (b^2*c^5*x^4 + 2*b^2*c^3*x^2 + b^2*c)*sqrt(c^2*x^2 + 1))*log(c*x + sqrt(c^2*x^2 + 1)) + (a*b*c^5*x^
4 + 2*a*b*c^3*x^2 + a*b*c)*sqrt(c^2*x^2 + 1)) + integrate(((c^3*(m - 4)*x^3 + c*(m - 1)*x)*(c^2*x^2 + 1)*x^m +
(2*c^4*(m - 4)*x^4 + c^2*(3*m - 4)*x^2 + m)*sqrt(c^2*x^2 + 1)*x^m + (c^5*(m - 4)*x^5 + c^3*(2*m - 3)*x^3 + c*
(m + 1)*x)*x^m)/((a*b*c^7*x^7 + 2*a*b*c^5*x^5 + a*b*c^3*x^3)*(c^2*x^2 + 1)^(3/2) + 2*(a*b*c^8*x^8 + 3*a*b*c^6*
x^6 + 3*a*b*c^4*x^4 + a*b*c^2*x^2)*(c^2*x^2 + 1) + ((b^2*c^7*x^7 + 2*b^2*c^5*x^5 + b^2*c^3*x^3)*(c^2*x^2 + 1)^
(3/2) + 2*(b^2*c^8*x^8 + 3*b^2*c^6*x^6 + 3*b^2*c^4*x^4 + b^2*c^2*x^2)*(c^2*x^2 + 1) + (b^2*c^9*x^9 + 4*b^2*c^7
*x^7 + 6*b^2*c^5*x^5 + 4*b^2*c^3*x^3 + b^2*c*x)*sqrt(c^2*x^2 + 1))*log(c*x + sqrt(c^2*x^2 + 1)) + (a*b*c^9*x^9
+ 4*a*b*c^7*x^7 + 6*a*b*c^5*x^5 + 4*a*b*c^3*x^3 + a*b*c*x)*sqrt(c^2*x^2 + 1)), x)

Giac [N/A]

Not integrable

Time = 0.34 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\int { \frac {x^{m}}{{\left (c^{2} x^{2} + 1\right )}^{\frac {5}{2}} {\left (b \operatorname {arsinh}\left (c x\right ) + a\right )}^{2}} \,d x } \]

[In]

integrate(x^m/(c^2*x^2+1)^(5/2)/(a+b*arcsinh(c*x))^2,x, algorithm="giac")

[Out]

integrate(x^m/((c^2*x^2 + 1)^(5/2)*(b*arcsinh(c*x) + a)^2), x)

Mupad [N/A]

Not integrable

Time = 2.77 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00 \[ \int \frac {x^m}{\left (1+c^2 x^2\right )^{5/2} (a+b \text {arcsinh}(c x))^2} \, dx=\int \frac {x^m}{{\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}^2\,{\left (c^2\,x^2+1\right )}^{5/2}} \,d x \]

[In]

int(x^m/((a + b*asinh(c*x))^2*(c^2*x^2 + 1)^(5/2)),x)

[Out]

int(x^m/((a + b*asinh(c*x))^2*(c^2*x^2 + 1)^(5/2)), x)